What Does Antenna Gain Mean?

  • Question: how can an antenna increase the signal without increasing transmitter power?
  • Gain describes radiation in a particular direction, relative to a lossless isotropic antenna with the same input power
    • It redistributes power in direction; it doesn’t create power (cf. EIRP)
  • The engineering question: where does that stronger signal need to go? (see Antenna Coverage)

Isotropic and Omnidirectional

  • Isotropic: equal radiation in every direction
  • Omnidirectional: uniform in one plane
  • Dipole example (3-D pattern plus two cuts):
    • Azimuth-plane cut: a circle — omnidirectional
    • Elevation-plane cut: a figure-eight with nulls along the dipole axis

WARNING

  • Omnidirectional ≠ isotropic: a dipole still has nulls along its axis

The Receive Antenna and Effective Area

  • Receive antenna captures
    • 𝑃𝑟=𝑆𝐴𝑒
    • 𝑆: incident power flux density (W/m²)
    • 𝐴𝑒: effective collecting area (m²)
    • 𝑃𝑟: available received power (W)
  • Physical area of a circular aperture, and effective area:
    • 𝐴=𝜋𝐷24,𝐴𝑒=𝜂ap𝐴
    • 𝜂ap = aperture efficiency; use 𝜂ap=0.55 for our examples
    • Illumination, spillover, blockage, and surface accuracy affect how well the physical aperture contributes
    • Aperture efficiency’s meaning differs from radiation efficiency alone

Frequency and Antenna Size

  • 𝜆≈0.300𝑓(𝑓in GHz,𝜆in m)
FrequencyWavelengthA 1 m aperture spans
2.1 GHz0.143 m7 wavelengths
8.4 GHz0.0357 m28 wavelengths
  • The antenna’s size in wavelengths determines much of its behavior

Gain from Diameter and Frequency

  • Gain = effective area ÷ isotropic effective area

Reflector Gain

  • [𝐺]=17.81+20log10(𝐷)+20log10(𝑓)
  • 𝐷 in meters, 𝑓 in GHz, [𝐺] in dBi; circular aperture, all logs base 10
  • 17.81 includes efficiency 0.55 and all constants
  • Doubling diameter or frequency increases gain by 20log102=6.02dB

A 1 m Antenna at 8.4 GHz

  • Given 𝐷=1.00m, 𝑓=8.4GHz (assumes 𝜂ap=0.55)
  • [𝐺]=17.81+20log10(1.00)+20log10(8.4)=17.81+0.00+18.49=36.30dBi
  • Predict, then check:
    • Double 𝐷, fixed frequency: Δ[𝐺]=20log10(2)=+6.02dB
    • Double frequency, fixed 𝐷: Δ[𝐺]=20log10(2)=+6.02dB
    • Double both: gain increases 12.04 dB

Far-Field Model (Optional)

  • The gain/pattern model assumes the far field; for an electrically large aperture:
    • 𝑅≳6.67𝐷2𝑓
    • 𝐷 and 𝑅 in meters, 𝑓 in GHz; also require 𝑅≫𝐷 and 𝑅≫0.300/𝑓
    • (This is 2𝐷2/𝜆 with 𝜆=0.300/𝑓)
  • At 8.4 GHz:
    • 3 m aperture: about 504 m
    • 70 m aperture: about 274,000 m

Gain in Linear Form

  • Class 4 (lunar link tools) writes the same model linearly:
    • 𝐺=𝜂(𝜋𝐷𝑓𝑐)2
    • For 𝜂=0.55: [𝐺]=17.8+20log10(𝐷/m)+20log10(𝑓/GHz)
  • Lunar link at 8.4 GHz: 0.3 m transmit dish → 25.8 dBi; 34 m receive dish → 66.9 dBi (signal budget)

Homework 3: Gain and Beamwidth

Homework 3, Problem 1

  • Circular reflector, 𝐷=0.80m, 𝑓=7.50GHz, aperture efficiency 0.55
    • (a) Peak gain in dBi and full HPBW in degrees
    • (b) Double 𝐷 at fixed 𝑓: gain change, new gain, new HPBW
    • (c) Restore 𝐷 and double 𝑓 to 15.00 GHz: gain change and HPBW; why is this insufficient to determine the received-power change?
  • Using [𝐺]=17.81+20log10(𝐷)+20log10(𝑓) and HPBW≈21/(𝑓𝐷) degrees:
CaseGain [𝐺] (dBi)Change (dB)HPBW (°)
𝐷=0.80 m, 𝑓=7.50 GHz33.37Reference3.50
Double 𝐷 to 1.60 m39.39+6.021.75
Double 𝑓 to 15.00 GHz39.39+6.021.75